Highest point of a geodesic (vertex)
The vertex of a geodesic: the northernmost point it reaches, where it runs due east or west, and how far along the line from the start it lies.
Planning and education aid. Not for primary navigation. Full disclaimer
The geodesic peaks at 53.671067616°, -22.988028393°.
- Vertex longitude
- Distance to the vertex
- Between the two points
- Azimuth at the equator
Provenance
- Computed by
- navigation.geodesic.vertex 1.0.1, core 0.1.0
- Model
- Clairaut's relation on the auxiliary sphere: sin α₀ = sin α₁ cos β₁ and σ₁ = atan2(sin β₁, cos α₁ cos β₁); the northern vertex is at σ = 90°, reached by the direct problem in arc length from the start
- Accuracy
- Exact to rounding: the azimuth at the vertex is 90° to within 1e-9°
- Notes
- None
- Cites
- Karney, C. F. F., Journal of Geodesy, Algorithms for geodesics
Something look off?
How we got thisFormula, worked example, sources, and proof
Model: Clairaut's relation on the auxiliary sphere: sin α₀ = sin α₁ cos β₁ and σ₁ = atan2(sin β₁, cos α₁ cos β₁); the northern vertex is at σ = 90°, reached by the direct problem in arc length from the start
Show your work
Arc from the equator crossing
σ₁ = atan2(sin β₁, cos α₁ cos β₁)β₁ = 40.546223497°, α₁ = 51.381647858°= 53.88664819°Vertex latitude
direct problem to σ = 90°36.11335181° of arc from the start= 53.671067616°
The same steps an agent gets from the MCP server with explain: true.
Accuracy: Exact to rounding: the azimuth at the vertex is 90° to within 1e-9°
When to use this: Use this to find the highest latitude a great-circle route reaches, and whether it reaches it on the way. A route from New York to London tops out at 53.7 degrees north, well above either end, which is what decides whether it crosses an area of operations, a weather band or an airspace you care about.
Limitations: The vertex need not lie between the two points: when it does not, the route never reaches that latitude, and the `within` field says so -- reading the latitude without it is the mistake this tool invites. Vertices repeat around the globe, and the one reported is the one nearest the start, which may be behind it at a negative distance. A geodesic along the equator has no vertex, and a meridian's vertex is the pole, where longitude names nothing.
Worked example: The JFK to London geodesic. Source: Karney (2013) auxiliary sphere; GeographicLib GeodSolve -a. It is golden test vector v001, and every build checks the tool still gives its answer within its tolerance.
You enter
- Start latitude
- 40.6413 deg
- Second point latitude
- 51.47 deg
- Start longitude
- -73.7781 deg
- Second point longitude
- -0.4543 deg
You get
- Vertex latitude
- 53.671067616°
- Vertex longitude
- -22.988028393°
- Distance to the vertex
- 4,014,306.918 m
- Between the two points
- yes
- Azimuth at the equator
- 36.420816908°
Review: Not yet independently reviewed by a geodesist.
Last verified: 2026-09-18, when a maintainer last confirmed this tool's sources at the issuer. See the sources ledger.
Status: version 1.0.1, core 0.1.0. See this tool in the verification report.
Changes
- 2026-09-23, fixed: Short distances lost their meaning: a 0.859 m geodesic showed as 0.001 km. Distances in the navigation tools (version 1.0.1) still show to the meter in kilometers, but a short one now keeps three significant digits, down to the millimeter, so it shows as 0.000859 km. Differences such as the rhumb line's extra distance keep fixed decimals. Values are unchanged. Changelog
Checked against: 21 golden test vectors (download the test vectors, each with its source and tolerance). See how results are checked and every source.
Sources
- Algorithms for geodesics, Karney, C. F. F., Journal of Geodesy, Vol. 87, No. 1. pp. 43-55.